Leetcode: Merge Two Sorted Lists
You are given the heads of two sorted linked lists list1
and list2
.
Merge the two lists in a one sorted list. The list should be made by splicing together the nodes of the first two lists.
Return the head of the merged linked list.
Example 1:
Input: list1 = [1,2,4], list2 = [1,3,4]
Output: [1,1,2,3,4,4]
Example 2:
Input: list1 = [], list2 = []
Output: []
Example 3:
Input: list1 = [], list2 = [0]
Output: [0]
Constraints:
- The number of nodes in both lists is in the range
[0, 50]
. -100 <= Node.val <= 100
- Both
list1
andlist2
are sorted in non-decreasing order.
Solution: Simply use the Merge part of Merge Sort
Working code in C#
/**
* Definition for singly-linked list.
* public class ListNode {
* public int val;
* public ListNode next;
* public ListNode(int val=0, ListNode next=null) {
* this.val = val;
* this.next = next;
* }
* }
*/
public class Solution
{
public ListNode MergeTwoLists(ListNode list1, ListNode list2)
{
if (list1 == null && list2 == null)
return null;
var head = new ListNode();
var current = head;
while (list1 != null || list2 != null)
{
if (list1 == null)
{
current.next = list2;
list2 = list2.next;
}
else if (list2 == null)
{
current.next = list1;
list1 = list1.next;
}
else if (list1.val < list2.val)
{
current.next = list1;
list1 = list1.next;
}
else
{
current.next = list2;
list2 = list2.next;
}
current = current.next;
}
return head.next;
}
}